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EI · 8 cards

Resistance and Conductors flashcards

8 cards with the formulas, rules and traps from this lesson. Answer in your head, then flip to check.

  1. Formula · 1/8

    How do you find a wire's resistance from its material and dimensions?

    : resistance () equals resistivity () times length L (m) divided by cross-sectional area A (). R rises with length and falls as area grows.

  2. Term · 2/8

    Resistance versus resistivity: what is the difference?

    Resistivity (, in ) is a property of the material alone. Resistance (R, in ohms) belongs to a specific object and also depends on its length and cross-sectional area.

  3. Common trap · 3/8

    If a wire's diameter is cut in half, what happens to its resistance?

    Area depends on diameter squared (), so area drops to 1/4 and resistance becomes 4 times larger, not 2 times. Always square the diameter ratio.

  4. Fact · 4/8

    How does temperature affect the resistance of metals versus semiconductors and carbon?

    Metals gain resistance when heated (copper about 0.4 percent per °C) because electrons scatter more. Semiconductors, carbon and NTC thermistors lose resistance as they warm (negative coefficient).

  5. Common trap · 5/8

    Which dissipates more power: a larger or smaller resistor?

    It depends on what is fixed. At the same voltage, , so the smaller R dissipates more. At the same current, , so the larger R dissipates more.

  6. Rule · 6/8

    How must an ohmmeter be used to measure a resistor correctly?

    Only on a de-energized circuit, with the part isolated (at least one lead disconnected), since the meter supplies its own current. Parallel paths, including your fingers on both probes, make the reading too low.

  7. Common trap · 7/8

    In the AWG system, is a 12 gauge wire thicker or thinner than 14 gauge?

    Thicker. A larger gauge number means a thinner wire, so 12 AWG has less resistance per foot and can carry more current than 14 AWG.

  8. Term · 8/8

    Open circuit versus short circuit?

    Open: a break in the path with effectively infinite resistance, so no current flows (the source voltage can appear across the gap). Short: an unintended very low-resistance path bypassing the load, causing very large current and heat.

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