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Functions, Patterns and Sequences

Function and pattern questions reward clear reading more than heavy computation. This lesson defines a function as an input-output rule, teaches function notation, and practices evaluating at fractions and decimals and finding inputs from a given output. You will decide whether a relation is a function, determine domain and range, spot domain restrictions, and read tables, ordered pairs and graphs, including the vertical line test.

Video lesson: Functions, Patterns and Sequences

Video transcript

0:00 Welcome to this explainer. Look, if the ASVAB math section has you feeling a little stressed out, you are definitely not alone. A lot of people feel intimidated by this subtest, but I promise you, once you see the hidden structure behind functions, patterns, and sequences, it's all gonna click. And here is the absolute best part. The ASVAB doesn't allow calculators, which means every single method we look at today is intentionally designed to be solved completely by hand, or just mentally in your head. You've got this. Here's our quick roadmap for today. We are going to cover functions and graphs, linear rules and sequences, and complex patterns. Then we'll dive right into step-by-step worked examples, wrap up with common pitfalls, and finally do some practice questions to check your confidence. All right, let's jump straight into section 1, functions and graphs, and what we like to call the vending machine rule. So what actually is a function? Honestly, you can just think of it exactly like a vending machine. It's a strict input output rule. If you press a specific button, you must get the exact same snack every single time. Take a look at the left side here.

1:04 Multiple inputs, like the numbers 1 and 2, can share an output of 5, and that's perfectly fine. It's kind of like getting the exact same bag of chips from two different buttons. But now look at the right side. One input, the number 2, maps to two completely different outputs, 4 and 6. If you press 1 button and get chips one day, but a candy bar the next, well, that machine is broken. In math terms, it is simply not a function. Linear rules and sequences, where we start finding the pattern. In linear sequences, numbers change by a totally constant predictable rate. To find this rate of change without a calculator, all you do is compare the change in your output with the change in your input. Look at the little table we have here. Our x, the input, goes from 1 to 4. Well, that's a rise of 3. Our y, the output, goes from 4 to 13. That's a rise of 9. Simply divide the change in your output by the change in your input. 9 divided by 3 gives us a really neat slope or rate of change of exactly 3. But what happens when things get a little tricky?

2:06 That brings us to section 3, complex patterns going beyond the basics. Right, so not every pattern is going to hand you the exact same jump every single time. Take a look at the sequence, 1, 4, 9, 16. The gaps between these terms aren't constant at all. The first gap is 3, then it's 5, then it's 7. But if you look at the gaps of those gaps, you'll notice they're rising steadily by 2 every time. Whenever that second difference is constant, like we see right here, you're dealing with what's called a quadratic pattern, which is basically just squaring your input. Think about it. 1 squared is 1, 2 squared is 4, 3 squared is 9, and so on. Alright, section 4. Step by step worked examples. This is where we put it all together. We are going to apply these rules and walk through 8 exact examples line by line right here on screen, with no skipped steps. For example, 1, we need to evaluate the function for an input of negative 3. So we substitute negative 3 using parentheses. Let me tell you, writing those parentheses is a vital habit to keep your mental arithmetic tidy.

3:06 Notice step 2. We make sure we square the negative 3 properly first, which gives us a positive 9. Then we have minus a negative 3, which naturally becomes a plus 3. So working it out, 2 times 9 is 18, 18 plus 3 is 21, and 21 plus 4 gives us our final answer of 25. On to example 2. Here we're inferring a linear rule straight from a table. By spotting that the output rises by 6, every time the input rises by 2, we can mentally calculate our slope. 6 divided by 2 is 3. Now we just work backward to find our starting point, the B. If we plug our slope of 3, and our first pair of 1 and 2 into the classic Y equals MX plus B formula, we get 2 equals 3 times 1 plus B. So 3 plus what equals 2? It has to be negative 1. Our final rule is Y equals 3x minus 1. Okay, example 3 shows an arithmetic sequence where we're basically just adding 4 each time. Now to find the 15th term, we don't actually take 15 steps.

4:09 Since we are already on the first step, we only need to take 14 more steps of 4 from our starting number. 6 plus 14 times 4 gives us 62. Then to find the sum of all 15 of those terms, we just average the first term, 6, and the last term, 62, and multiply that average by 15. Run those numbers, and that gives us an answer of 510. Let's look at geometric growth in example 4. Say we start with 300 bacteria that double every hour. After 5 hours, doubling means multiplying by 2 to the 5th power. 2 to the 5th power is 32. So we just multiply our starting amount of 300 by 32, which comes out to 9,600. It's totally doable without a calculator if you just break it down. Example 5 is what we call a composition of functions. Honestly, the ultimate key trick here is to always, always work from the inside out. We solve the inner part, Q of 1, first. 3 times 1 plus 2 equals 5. Then you just take that result of 5 and feed it right into the outer function P.

5:13 5 squared is 25, minus 1 is 24. See? Step by step. For example 6, we're looking for the next term in a sequence. We check the gaps between the numbers, 3, 5, 7, 9, and suddenly we realize the gaps themselves are steadily rising by 2. So logic tells us the next gap has to be 11. We simply add 11 to our last number, 28, and boom, our answer is 39. Now example 7 involves piecewise rules. That sounds super intimidating, but it just means the function has different instructions depending on the input. We carefully check which condition our input meets before doing any math. An input of 2 fits the first rule, because 2 is less than or equal to 2. So 5 minus 2 is 3. An input of 4 fits the second rule because 4 is greater than 2. So 2 times 4 is 8. Add those two results together and you get 11. Finally, in example 8, we restrict the domain. In math, there's a golden rule. You literally cannot divide by 0. It breaks everything. So we have to ensure the bottom of our fraction never equals 0.

6:18 If x squared minus 9 equals 0, then x squared would equal 9. This means x could be either a 3 or a negative 3. So both of those specific inputs are completely banned from this function. Pitfalls and exam review. Let's talk about avoiding traps. Listen, the test makers know exactly which easy mistakes to look for. But avoiding these simple notation errors will instantly save your score. First, remember that f of x is just a label for the output. It is never ever f times x. Next, always keep parentheses around your negative numbers when substituting so you don't mess up your signs. In sequence formulas, remember to use n minus 1, because reaching your first term takes 0 steps, not one step. And always keep this straight. Arithmetic means adding a constant difference. Geometric means multiplying by a constant ratio. All right, section 6, check yourself practice. Time to test that confidence. Let's put everything we discovered to the test with two actual check yourself questions drawn right from the ASVAB study material. Here is question 1.

7:23 If f of x equals 3x plus 5, what is the value of f of 4? Go ahead and pause the explainer right now and try to solve this mentally without a calculator. And we're back. The correct answer is d, 17. All you do is substitute the 4 in for x and follow your basic arithmetic steps. 3 times 4 is 12 and 12 plus 5 is 17. Pretty straightforward, right? Okay, let's look at question 2. Which set of ordered pairs is not a function? Once again, pause the explainer right now, think back to our vending machine rule from earlier and see if you can spot the trap. All right, option a, the correct choice here. Why? Because in option a, the input of 1 tries to spit out both a 3 and a 7. That proves the mathematical vending machine is totally broken. And there you go. You've just conquered functions, sequences, and formulas entirely in your head. But here's a thought to take with you before you test. If you can decode the hidden rules inside these ASVAB numbers today, what other complex systems in your future career are just waiting for you to find the pattern? Keep practicing, trust your logic, and I'll catch you in the next explainer.

Visual lesson

Lesson slides

15 slides
Functions, Patterns and Sequences – slide 1 of 15

Learning Outcomes and Exam Fit

This lesson trains you to evaluate functions written in f(x) notation, find the input that produces a given output, and decide whether a relation is a function. You will read domain and range from tables and graphs, build rules for arithmetic and geometric sequences, extend patterns, and handle composite and piecewise functions. These skills belong to ASVAB Mathematics Knowledge algebra, although no single question type is guaranteed.

Function as Input–Output Rule

A function is a rule that assigns each input exactly one output. Think of a vending machine: pressing button B4 should always drop the same snack. If one button could give two different snacks, the machine would not behave like a function. Inputs are usually called x, outputs y or f(x). Different inputs may share an output, but one input may never have two.

Reading Function Notation

The notation is read as f of x and means the output of f at input x; it is not multiplication. For

the value means replace x by 2:

4(2) + 1 = 9

Evaluating at Fractions and Decimals

Fractions and decimals substitute the same way; just keep the arithmetic tidy. If

then
and
g(0.5) = 3 - 2 = 1

Put parentheses around every substituted value, especially negatives.

Finding Inputs from an Output

To find which input gives a certain output, set the rule equal to that output and solve. If

f(x) = 5x - 3

and the output is 22, then

5x - 3 = 22

so 5x = 25 and x = 5. Check:

5(5) - 3 = 22

Function or Not a Function?

A relation fails to be a function when one input is paired with two different outputs. The set {(2, 4), (3, 9), (2, 6)} is not a function because 2 maps to both 4 and 6. An identical pair listed twice, or several inputs sharing one output, as in {(1, 5), (2, 5)}, is still a function.

Two mapping diagrams: inputs 2 and 3 mapped to outputs 4, 6 and 9 with 2 going to both 4 and 6, so not a function; inputs 1 and 2 both mapped to 5, which is still a function.

Domain and Range

The domain is the set of all allowed inputs, and the range is the set of outputs actually produced. For the pairs (1, 2), (3, 2) and (5, 8), the domain is {1, 3, 5} and the range is {2, 8}. On a graph, the domain is the horizontal spread and the range is the vertical spread.

Points (1, 2), (3, 2) and (5, 8) with dashed drops to the x-axis marking the domain {1, 3, 5} and dashed lines to the y-axis marking the range {2, 8}.

Domain Restrictions

Some inputs are banned because they cause impossible arithmetic. A denominator cannot be zero, so

excludes

x = -2

In real numbers, a square root needs a nonnegative inside, so requires

Two number lines: for k(x) = 5/(x + 2) everything is shaded except an open circle at −2; for √(x − 4) a closed dot at 4 with shading to the right.

Tables, Ordered Pairs, and Graphs

The same function can appear as a rule, a table, a list of ordered pairs, or a graph. A table row with x = 2 and y = 7 is the ordered pair (2, 7) and one plotted point. To read f(4) from a graph, find 4 on the horizontal axis, move straight up or down to the curve, and read its height.

Table row x = 2, y = 7 plotted as the point (2, 7) on a curve; to read f(4), an arrow goes up from 4 on the x-axis to the curve, then across to the y-axis, marked f(4) = ?.

The Vertical Line Test

To test whether a graph shows a function, imagine sliding a vertical line across it. If any vertical line touches the graph more than once, some input has two outputs, so the graph is not a function. A parabola opening upward passes; a circle fails, since a vertical line through its middle hits it twice.

Vertical line test: a dashed vertical line meets an upward parabola once, above the x-axis (function), but a vertical line through the middle of a circle meets it twice (not a function).

Linear Functions and Constant Change

A linear function has the form f(x) = mx + b. Each time x increases by 1, the output changes by the same amount m, the slope. The constant b is the output when x = 0. For

f(x) = -2x + 7

the outputs for x = 0, 1, 2, 3 are 7, 5, 3, 1, dropping by 2 each step.

Graph and table of f(x) = −2x + 7: points (0, 7), (1, 5), (2, 3) and (3, 1) on a line; each step of +1 to the right drops by 2, and b = 7 is the output at x = 0.

Rate of Change from a Table

Rate of change compares the change in output with the change in input:

From (1, 4) to (4, 13), the output rises 9 while the input rises 3, so the rate is 3 per unit.

Line through (1, 4) and (4, 13) with a slope triangle: run +3 and rise +9, so the rate is 9 ÷ 3 = 3 per unit.

Function Rules in Word Contexts

Word problems often hide a function. A gym charges a 25-dollar sign-up fee plus 30 dollars per month, so the cost is

C(m) = 30m + 25

Here 30 is the rate per month and 25 is the starting value. After 6 months,

C(6) = 180 + 25 = 205 dollars
Graph of the gym cost C(m) = 30m + 25 for m = 0 to 6 months: it starts at the 25-dollar sign-up fee, rises 30 dollars for each month (+1 month, +$30 step), and reaches (6, 205).

Arithmetic Sequences

An arithmetic sequence adds the same number, the common difference d, to get each new term. In 9, 13, 17, 21, ..., d = 4, so the next term is 25. A negative d makes the terms fall, as in 20, 17, 14, 11, where

d = -3
Number lines with hop arrows: 9, 13, 17, 21 adding 4 each time to reach 25 (d = 4), and 20, 17, 14, 11 subtracting 3 each time (d = −3).

The nth-Term Formula for Arithmetic Sequences

The nth term is

For 5, 8, 11, ..., the 20th term is

5 + 19(3) = 62

Use n - 1, not n, because reaching the first term takes no steps.

Hop diagram for 5, 8, 11, …: term 1 needs 0 hops, then +3 hops reach term 20 after 19 hops (n − 1), so the 20th term is 5 + 19(3) = 62.

Working Backward in Arithmetic Sequences

You can run the formula backward. A sequence starts at 3 with d = 5. Which term is 48? Solve

3 + 5(n - 1) = 48
n - 1 = 9

so n = 10.

Sum of an Arithmetic Sequence

To add the first n terms, average the first and last terms and multiply by n:

For 2, 5, 8, ..., 20, which has seven terms, the sum is

7(22)/2 = 77
The terms 2, 5, 8, 11, 14, 17, 20 with arcs pairing 2 + 20, 5 + 17 and 8 + 14, each 22; the middle term 11 is half of 22, so 7 terms × 22 ÷ 2 = 77.

Geometric Sequences

A geometric sequence multiplies by the same number, the common ratio r, each time. Find r by dividing a term by the one before it. In 5, 15, 45, 135, ...,

so the next term is 405. When r is between 0 and 1, the terms shrink.

Geometric sequence 5, 15, 45, 135, 405 with a × 3 hop between each pair of terms; r = 15 ÷ 5 = 3.

The nth-Term Formula for Geometric Sequences

The nth term of a geometric sequence is

For 4, 8, 16, ..., r = 2, so the 7th term is

Growth and Decay Patterns

Repeated multiplication models growth and decay. A town of 2,000 people growing 10% per year multiplies by 1.1 each year: 2,200, then 2,420. A car worth 20,000 dollars that loses 20% per year keeps 80% each time: 16,000, then 12,800 dollars. Growth uses r greater than 1; decay uses r between 0 and 1.

Bar charts: growth 2,000 → 2,200 → 2,420 people, multiplying by 1.1 (r > 1); decay 20,000 → 16,000 → 12,800 dollars, multiplying by 0.8 (0 < r < 1).

Recognizing Quadratic-Like Patterns

If the gaps between terms are not constant but the gaps of those gaps are, the pattern is quadratic. In 1, 4, 9, 16, ..., the gaps 3, 5, 7 rise by 2, and the terms are . A pattern such as 3, 6, 11, 18, ... follows , so the next term is 27.

Square dot arrays of 1, 4, 9 and 16 dots; the new dots added each time number 3, 5 and 7.

Recursive Definitions

A recursive rule gives a starting term and says how to get each term from the one before. With

and

the terms are 3, then 7, then 19, then 55. You must build the terms one at a time, in order.

Alternating and Multi-Rule Patterns

Some patterns switch between two rules or weave two sequences together. In 2, 5, 4, 7, 6, 9, ..., the steps alternate between adding 3 and subtracting 1, so the next term is 8. In 1, 10, 2, 20, 3, 30, ..., odd positions count 1, 2, 3 while even positions count by tens, so the next term is 4.

Two patterns: 2, 5, 4, 7, 6, 9 with hops alternating +3 above and −1 below, giving the next term 8; and 1, 10, 2, 20, 3, 30 where odd places count 1, 2, 3 and even places count 10, 20, 30, giving the next term 4.

Composition of Functions

means apply g first, then feed that result into f. With

f(x) = x + 5

and g(x) = 2x, g(4) = 8 and f(8) = 13. Order matters:

g(f(4)) = g(9) = 18
Function machines: for f(g(4)), 4 goes into g (× 2) to give 8, then into f (+ 5) to give 13; for g(f(4)), 4 goes into f to give 9, then into g to give 18.

Piecewise Rules

A piecewise function uses different rules on different parts of the domain. Suppose

when

and

when

then
r(-3) = 1

and r(2) = 6. At the boundary x = 1, the second rule applies, so r(1) = 3.

Graph of r(x): the ray y = x + 4 for x < 1 ends in an open circle at (1, 5), and the ray y = 3x for x ≥ 1 starts at a closed dot at (1, 3), with points (−3, 1) and (2, 6) and a dashed boundary at x = 1, so r(1) = 3.

Sequence Word Problems

Many word problems are sequences in disguise. A runner trains 2 miles the first week and adds half a mile each week, so the weekly distance is arithmetic with first term 2 and d = 0.5. Week 9 is

2 + 8(0.5) = 6 miles

Doubling, halving, or a fixed percent change signals a geometric pattern instead.

Tables with Unequal Input Steps

When the inputs in a table do not rise by 1, divide each output change by its input change. If x goes 0, 2, 6 and y goes 1, 7, 19, the changes are 6 over 2 and 12 over 4, both 3, so

y = 3x + 1
Table with x = 0, 2, 6 and y = 1, 7, 19: x rises +2 then +4, y rises +6 then +12; 6 ÷ 2 = 3 and 12 ÷ 4 = 3, so y = 3x + 1.

Fast No-Calculator Checks

Check answer choices instead of recomputing from scratch. If

f(x) = 3x - 2

and a choice claims x = 6 gives an output of 19, compute 16 and reject it; x = 7 gives 19. For sequences, confirm the pattern with two consecutive gaps or ratios before extending it. Watch signs: an even power of a negative number is positive.

Worked Example 1 — Function Evaluation

Problem: Find for

Step 1: Replace every x with (−3). Always use parentheses around a negative input.

Step 2: Do the exponent first. (−3)² =

(−3) × (−3) = 9

because a negative times a negative is positive.

Step 3: Multiply:

2 × 9 = 18

Subtracting a negative is the same as adding, so −(−3) = +3.

Step 4: Add from left to right:

18 + 3 = 21
then
21 + 4 = 25

Answer: 25.

Check: A common mistake is writing −3² = −9, which would give

2(−9) + 3 + 4 = −11

Squaring a negative number always gives a positive result, so the term 2x² must be positive: 18. Then

18 + 3 + 4 = 25

is right.

Worked Example 2 — Infer a Linear Rule

Problem: A table gives the points (1, 2), (3, 8) and (5, 14). Find the linear rule y = mx + b.

The table points (1, 2), (3, 8) and (5, 14) plotted on axes labeled 2 to 14, with a rise of +6 and a run of +2 from (1, 2) to (3, 8); the rule y = mx + b has m = ? and b = ?.

Step 1: Find the slope. From (1, 2) to (3, 8), x goes up

3 − 1 = 2

and y goes up

8 − 2 = 6

Step 2: Find b. Put the slope and the point (1, 2) into y = mx + b.

Step 3: Subtract 3 from both sides:

2 − 3 = −1

Answer:

Check: Test all three points. x = 1:

3 − 1 = 2

x = 3:

9 − 1 = 8

x = 5:

15 − 1 = 14

All three match the table.

Worked Example 3 — Arithmetic Term and Sum

Problem: For the sequence 6, 10, 14, ..., find the 15th term and the sum of the first 15 terms.

Step 1: Find the common difference:

10 − 6 = 4
and
14 − 10 = 4

so d = 4. The first term is 6.

Step 2: To reach the 15th term, start at the 1st term and add d fourteen times (

15 − 1 = 14

).

Multiply first:

14 × 4 = 56
then
6 + 56 = 62

Step 3: For the sum, use: number of terms × (first + last) ÷ 2. First add

6 + 62 = 68

Step 4: Halve 68 first to keep the numbers small:

68 ÷ 2 = 34
then
15 × 34 = 300 + 210 = 510

Answer: The 15th term is 62, and the sum is 510.

Check: The average term is

(6 + 62) ÷ 2 = 34

and 15 terms at an average of 34 make 510.

Worked Example 4 — Geometric Growth

Problem: A culture of 300 bacteria doubles every hour. How many are there after 5 hours?

Step 1: Doubling means multiplying by 2 each hour. After 5 hours you multiply by 2 five times, which is .

Step 2: Work out the power:

2 × 2 = 4
4 × 2 = 8
8 × 2 = 16
16 × 2 = 32

Step 3: Multiply:

300 × 32 = 3 × 32 × 100 = 96 × 100 = 9,600

Answer: 9,600 bacteria.

Check: Track it hour by hour: 300, then 600, 1,200, 2,400, 4,800, and 9,600 after hour 5.

Hour timeline from 0 to 5 with a × 2 hop each hour: 300, 600, 1,200, 2,400, 4,800 and 9,600 after hour 5.

Worked Example 5 — Composition

Problem: With

and

find .

Function machines: 1 goes into q: 3x + 2 first, giving ?, which then goes into p: x² − 1, giving ?.

Step 1: Work from the inside out. First find q(1) by putting 1 into q.

Step 2: The output of q becomes the input of p. So p(q(1)) = p(5).

Step 3: Square 5:

5 × 5 = 25

Then subtract 1.

Answer: 24.

Check: Be careful not to work outside in.

p(1) = 1 − 1 = 0

and q(0) = 2, which is q(p(1)), a different question. For p(q(1)), q always goes first: q(1) = 5, p(5) = 24.

Worked Example 6 — Quadratic-Like Pattern

Problem: Find the next term of 4, 7, 12, 19, 28, ...

Step 1: Find the gaps between neighboring terms:

7 − 4 = 3
12 − 7 = 5
19 − 12 = 7
28 − 19 = 9

Step 2: The gaps 3, 5, 7, 9 go up by 2 each time, so the next gap is

9 + 2 = 11

Step 3: Add the next gap to the last term.

Step 4: Find a rule as a second method. Compare each term with the square numbers 1, 4, 9, 16, 25: every term is 3 more (

1 + 3 = 4
4 + 3 = 7
9 + 3 = 12

and so on). So the nth term is .

The next term is term number 6.

Answer: 39.

Check: Both methods give 39. Also check the rule on term 5: 5² +

3 = 25 + 3 = 28

which matches the sequence.

Difference table for 4, 7, 12, 19, 28: the gaps 3, 5, 7, 9 rise by 2, so the next gap is 11 and the next term is 39.

Worked Example 7 — Piecewise and Boundary

Problem: Let

for

and

for

Find .

Graph of s(x) on square grid: the ray 5 − x for x ≤ 2 ends in a closed dot at x = 2, and the ray 2x for x > 2 starts with an open circle at x = 2; x = 2 and x = 4 are marked with s(2) = ? and s(4) = ?.

Step 1: Decide which rule to use for x = 2. The first rule covers x ≤ 2, which includes 2 itself. So use 5 − x.

Step 2: For x = 4, the number 4 is greater than 2, so use the second rule, 2x.

Step 3: Add the two results.

Answer: 11.

Check: The boundary is the tricky part. If you wrongly used 2x for x = 2, you would get 4 instead of 3 and a total of 12. Since ≤ includes 2, the first rule is correct and the total is 11.

Worked Example 8 — Domain Restriction

Problem: Which inputs are excluded from the domain of

Step 1: You can never divide by zero. So find the x values that make the denominator zero.

Step 2: Add 9 to both sides.

Step 3: Which numbers squared give 9? Both

3 × 3 = 9
and
(−3) × (−3) = 9

Step 4: Think about the numerator. It is zero when

x = −1

but a zero on top is fine: 0 divided by a nonzero number is just 0.

Answer: x = 3 and

x = −3

are excluded. Every other real number is allowed.

Check: At x = 3 the bottom is

9 − 9 = 0

and at

x = −3

it is

9 − 9 = 0

so both fail. At

x = −1

the value is

0 ÷ (1 − 9) = 0 ÷ (−8) = 0

which is fine.

Number line from −5 to 5 shaded everywhere except open circles at −3 and 3, which are excluded; x = −1 is marked as allowed because m(−1) = 0.

Pitfalls and Distractor Patterns

Treating as f times x leads nowhere; it names an output. Dropping parentheses around negatives turns

into -9. Using n instead of n - 1 in the arithmetic formula overshoots by one step, which is why wrong choices often differ from the key by exactly d. Mixing up arithmetic and geometric patterns is avoided by checking whether gaps or ratios stay constant. Work compositions inside out, read piecewise boundary signs carefully, and remember that a repeated identical pair never breaks a function.

Final Exam-Ready Review

A function gives each input one output; use the vertical line test on graphs and look for one input with two outputs in lists. Evaluate by substituting in parentheses, and find an input by setting the rule equal to the output. Domains exclude zero denominators and negative square-root insides. Arithmetic sequences add d, with

Geometric sequences multiply by r, with

Check second differences for quadratic patterns, and work compositions inside out.

Quick review

What makes a relation a function?
Each input has exactly one output. {(1, 3), (2, 3)} is a function, since inputs may share an output; {(4, 1), (4, 7)} is not, since input 4 has two outputs. On a graph, use the vertical line test.
What does f(3) mean when f(x) = 2x − 5?
f(x) names the output at input x; it is not f times x. f(3) = 2(3) − 5 = 1. To find the input for a given output, write rule = output and solve for x.
Domain vs. range, and what restricts a domain?
Domain: allowed inputs. Range: outputs produced. Exclude inputs that make a denominator zero ( excludes 5) or a square root's inside negative ( needs x ≥ −1).
Rate of change (slope) from two points?
, change in output over change in input. From (2, 5) to (6, 17): m = 12/4 = 3. In f(x) = mx + b, b is the output when x = 0.
nth term of an arithmetic sequence?
, where is the first term and d the common difference. For 7, 11, 15, ...: . Using n instead of n − 1 overshoots by d.
Sum of the first n terms of an arithmetic sequence?
: the average of the first and last terms times the number of terms. 3, 7, 11, ..., 23 has 6 terms, so the sum is 6(26)/2 = 78.
nth term of a geometric sequence?
, where r is the common ratio (any term divided by the one before). For 3, 6, 12, ...: . Growth has r > 1; decay has 0 < r < 1.
How do you evaluate a composition f(g(x))?
Work inside out: compute g(x), then feed that result into f. With and g(x) = x + 1: f(g(2)) = f(3) = 9, but g(f(2)) = g(4) = 5, so order matters.

What next?

← Previous: Systems and Relationships

About this lesson

The sequence material covers arithmetic sequences, their nth-term formula, working backward and finding sums, then geometric sequences, growth and decay patterns, recursive definitions and alternating rules. Additional sections address linear functions and rate of change, quadratic-like patterns, composition of functions, piecewise rules, tables with unequal steps and fast no-calculator checks.

Eight worked examples apply these ideas, and a section on pitfalls and distractor patterns shows how wrong answers are built. The topic supports the Mathematics Knowledge subtest within the AFQT. The lesson takes about 39 minutes; a 20-question lesson test comes next.

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