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MC · lesson 6 of 12 · 110 min

Hydraulics and Pneumatics

Hydraulic lifts and air-powered tools both run on pressure, and this lesson shows how to calculate what they can do. It begins with pressure as force divided by area, pressure units, and gauge versus absolute pressure, then moves to Pascal's principle, master and slave pistons, and a worked force-multiplication example. You will see why diameter is not piston area, how volume conservation limits piston travel, and why real systems lose some performance.

Video lesson: Hydraulics and Pneumatics

Video transcript

0:00 Welcome to this explainer. So if you're gearing up for the ASVAB, you probably already know that the mechanical comprehension section absolutely loves to test you on fluid power. And honestly, hydraulics and pneumatics can look incredibly intimidating at first glance, especially since the ASVAB doesn't let you use a calculator. But seriously, don't sweat it, take a deep breath. Today, I'm gonna be your friendly tutor. We're gonna break down all the math step by step. I'll show you exactly how to solve these problems entirely by hand and honestly, mostly just in your head. So you can walk into test day feeling completely confident. All right, let's dive into this. Here's a quick look at our roadmap. We're gonna hit fluid power and pressure, Pascal's principle, system components and flow, pneumatics, some critical traps and safety rules, and then finish up with a practice test. All right, let's jump straight into section one, fluid power and pressure. We need to define exactly what pressure is. Pressure equals force divided by area, P equals F over A. Basically, pressure just tells you how concentrated a force is over a given surface.

1:02 Let's look at this worked example. Say we have a force of 600 newtons pressing evenly on an area of 0.020 square meters. We just need to divide 600 by 0.020. Now, you might be wondering, how do we actually do that without a calculator? Well, there's a simple mental math trick. Just move the decimal place. 0.020 is exactly the same as 2 divided by 100. So just take 600, divide it by 2 to get 300, and then tack those two zeros right back on the end. Boom, 30,000 pascals. Now, here's a sneaky little trap that catches a ton of test takers. The difference between gauge pressure and absolute pressure. You see, most gauges read zero when they're just sitting open in the air. But in reality, the Earth's atmosphere is actually pushing down on us all the time with about 100 kilopascals of pressure. So absolute pressure equals your gauge pressure plus that atmospheric pressure. If your tire gauge reads 250 kilopascals, you have to add the 100 kilopascals of atmospheric pressure to get your true absolute pressure, which is 350 kilopascals.

2:08 This is absolutely crucial, because whenever you do gas law calculations on the test, you must use absolute pressure. Pascal's principle. Let's talk about pistons and force. Pascal's principle tells us that if you squeeze a confined fluid, that change in pressure is passed on undiminished to every single part of the fluid. This gives us the classic master slave piston setup, because the pressure is perfectly equal on both sides, force one over area one equals force two over area two. Imagine we have a small input piston of 5 square centimeters and a large output piston of 40 square centimeters. Our area ratio is 40 divided by 5, which is 8. That right there is your mechanical advantage. So if we apply a 60 Newton push to that small piston, we literally just multiply 60 by our advantage of 8. Do it in your head. 6 times 8 is 48, add the 0 back, 480 newtons. We just took a 60 Newton push and magically scaled it up to a 480 Newton output. But watch out, because here is a major ASVAB trap. The test makers absolutely love giving you the piston diameter instead of the area.

3:13 Remember, pistons are circles, and a circles area grows with the square of its diameter. So if you're comparing a 4 centimeter piston to a 2 centimeter piston, it is not just twice the area. You have to divide 4 by 2, which gives you 2, and then you have to square it. 2 squared is 4. That means a 4 centimeter piston has 4 times the area of a 2 centimeter one. Always, always square the diameter ratio. Now, as incredible as multiplying forces, you can't just create free energy out of nowhere. Gaining force always costs you travel distance. Because liquids don't compress, the volume of oil pushed out of the small cylinder perfectly matches the volume entering the large one. That means area 1 times distance 1 equals area 2 times distance 2. Let's say a small piston moves 120 cubic centimeters of fluid, and it spreads out under a large 20 square centimeter piston. You just divide them, 120 divided by 20. Just cross out the zeros on both ends in your head. 12 divided by 2 is 6 centimeters of lift. So you got a massive output force, but the trade-off is it only moved 6 centimeters. Let's look at section 3, system components and flow.

4:19 Every ideal math model needs actual real-world parts to work. First, the reservoir. That just stores the oil and lets trapped air escape. Then there's the relief valve, which is a crucial safety feature. It caps the maximum pressure by sending fluids safely back to the tank if things get dangerously intense. The directional valve simply chooses the flow path, like deciding whether a cylinder should extend or retract. But listen to this, the absolute most crucial component is the pump. A pump draws oil from the reservoir and shoves it into the system. And here is the key takeaway. A pump creates flow, not pressure. Pressure only builds up when that flowing oil actually meets resistance, like when it's trying to lift a really heavy load. So how fast does a cylinder actually extend? Well, it extends exactly as fast as the oil fills it up. Velocity, or speed, equals the flow rate divided by the piston area. Let's say our pump delivers 200 cubic centimeters per second into a cylinder that has a 40 square centimeter piston. We literally just divide 200 by 40. Again, just cross out the zero at the end of each number.

5:22 20 divided by four equals five. It's that simple. The cylinder extends at five centimeters per second. And this next example brilliantly illustrates the exact same concept, just using a narrowing pipe instead of a cylinder. Say a pump delivers 0.60 liters per second. First, we easily convert that. A liter is 1,000 cubic centimeters, so that's 600 cubic centimeters per second. Now, we're pushing that through a line with an area of 3.0 square centimeters. 600 divided by three gives us 200 centimeters per second. Finally, we can quickly convert that back to meters. 200 centimeters is exactly 2.0 meters per second. All right, time to shift gears to section four, pneumatics and Boyle's law. This is where we use fast, springy, compressed air instead of firm oil. The basic force rule is exactly the same, whether you're using oil or air. Force equals pressure times area. However, you do have to watch your units very closely. If the test gives you a pressure like 600 kilopascals, you have to convert that to regular pascals before you multiply. Kilo means 1,000, so 600 kilopascals is 600,000 pascals.

6:28 Multiply that by an area of 0.0025 square meters. To do this entirely in your head, just ignore the decimal for a second. Six times 25 is 150. Then, when you balance out the four decimal places against those five zeros, it leaves you cleanly at 1,500 newtons. Now, because air actually compresses, we have to use Boyle's law. That tells us pressure one times volume one equals pressure two times volume two. Essentially, pressure and volume are inversely related. Imagine a sealed pocket of air sitting at 100 kilopascals and taking up 12 liters of space. If we squeeze that volume down slowly to just three liters, think about it logically for a second. The volume was divided by four, right? So the pressure has to do the exact opposite. It multiplies by four. 100 times four gives us 400 kilopascals absolute. See, we didn't even need a calculator for that. Temperature also drastically affects compressed gas. If you have a sealed rigid tank and you start heating it up, the internal pressure is going to rise. Our formula for this is P1 over T1 equals P2 over T2. The absolute golden rule you have to remember here is that your temperature must be in Kelvin.

7:37 For example, if we take our 400 kilopascals, multiply it by our new hotter temperature of 308 Kelvin and then divide by the old cooler temperature of 280 Kelvin, that works out to a brand new pressure of 440 kilopascals. Let's move to section five, troubleshooting, safety, and traps. Here's what you need to watch out for. I want to put a massive mental warning sign on this next concept for you. This is literally one of the most common errors test takers make. Because we know there are 100 centimeters in a meter, people just naturally assume there are 100 square centimeters in a square meter. That is completely false. Area converts by the square of the length. 100 squared is 10,000. So one square meter is actually 10,000 square centimeters. If you just divide by 100, your answer is going to be off by a massive factor of 10,000. And I guarantee you, the test makers will have that exact wrong answer waiting for you as one of the multiple choice options. Don't fall for it. On the safety side of things, you really need to respect hazardous energy. Never, ever run your hand along a hose trying to feel for a leak.

8:42 A pinhole jet of highly pressurized hydraulic oil acts exactly like a microscopic needle. It can pierce right through your skin and inject toxic fluid directly into your body, which causes severe tissue damage. Always use a piece of cardboard or another tool to find those leaks. And make sure to depressurize the system first. The pressure ratings on these parts aren't suggestions. They are hard, dangerous limits. And finally, section six. Check yourself practice. Let's see how we're doing. OK, here's the first practice question. I'm going to read it aloud clearly. If you need some time to think it over, just pause the explainer before I reveal the answer. Question two. How is pressure defined for a force pressing evenly on a surface? A, force divided by area. B, force multiplied by area. C, area divided by force. D, force multiplied by distance. Go ahead and pause now if you need to think. All right, the correct answer is A, force divided by area. This links right back to our very first equation from the start of our session together. P equals F over A. Pressure is all about measuring how concentrated a force is on a surface.

9:45 If you nail that, you are doing great. Let's take a look at the final test question. A pneumatic tool is rated for three bar. What is this pressure in kilopascals? A, 0.3 kPa. B, 3,000 KPA. C, 30 KPA. D, 300 KPA. Take a second for one last mental math pause. 300 kilopascals. For this one, you just need to remember that one bar is exactly equivalent to 100 kilopascals. So three times 100 gives you 300. And there you go. You have just navigated the absolute hardest parts of mechanical comprehension without even touching a calculator. So the next time you see a massive excavator lifting tons of earth or an air tool spinning at lightning speed, I want you to ask yourself just how much invisible multiplied pressure is hiding inside those cylinders. Thanks for hanging out and good luck on the test.

Contents · 66 sections
  1. Learning objectives and exam boundaries
  2. Hydraulic versus pneumatic power
  3. Pressure is force divided by area
  4. Pressure units and conversions
  5. Gauge versus absolute pressure
  6. Pascal principle: transmitted pressure change
  7. Hydraulic master and slave pistons
  8. Worked force multiplication example
  9. Diameter is not piston area
  10. Volume conservation in an ideal lift
  11. Work and mechanical advantage
  12. Why real hydraulics are not perfect
  13. Hydraulic reservoir and pump roles
  14. Positive-displacement pump concept
  15. Hydraulic pressure relief valves
  16. Check valve versus directional valve
  17. Flow controls change speed
  18. Flow rate is volume per time
  19. Continuity through a narrowing line
  20. Hydraulic cylinder extension rate
  21. Hydrostatic pressure with depth
  22. Open and closed hydraulic circuits
  23. Single-acting cylinders
  24. Double-acting cylinders
  25. Hydraulic motor versus cylinder
  26. Hydraulic brakes as an application
  27. Hydraulic lifts and jacks
  28. Fluid viscosity and temperature
  29. Filters and contamination
  30. Leak versus trapped air symptoms
  31. What pneumatics uses
  32. Air compressors and stored energy
  33. Air preparation components
  34. Pressure regulator purpose
  35. Directional air valves
  36. Pneumatic cylinders and return springs
  37. Air pressure and an ideal force
  38. Boyle law at constant temperature
  39. Boyle-law worked example
  40. Temperature affects compressed gas
  41. Compressed air is not an ideal liquid
  42. Air flow and actuator speed
  43. Energy tradeoffs in pneumatics
  44. Pressure times area applies to both media
  45. Pressure and flow solve different problems
  46. Why equal piston pressure is not equal force
  47. Equivalent area units
  48. The cylinder displacement calculation
  49. Pressure drop through restrictions
  50. Hydraulic accumulators
  51. Pneumatic exhaust and mufflers
  52. Hydraulic return and tank line
  53. Pressure gauge placement
  54. Symptoms require several hypotheses
  55. Never use skin to seek leaks
  56. Hazardous energy isolation
  57. Compressed air cleaning restrictions
  58. Eye and hose hazards
  59. Pressure rating is a hard limit
  60. Reading a basic hydraulic diagram
  61. Reading a basic pneumatic diagram
  62. Worked comparison: force versus travel
  63. Worked comparison: pipe velocity
  64. Worked comparison: air spring
  65. Common ASVAB traps
  66. Final recap and independent practice
Visual lesson

Lesson slides

15 slides
Hydraulics and Pneumatics – slide 1 of 15

Learning objectives and exam boundaries

In this lesson you will learn to tell hydraulic systems from pneumatic ones, calculate pressure as force over area, apply Pascal's principle to connected pistons, relate piston travel to area and find cylinder speed from flow rate. You will use Boyle's law for compressed air and recognize the job of pumps, valves, regulators and cylinders. Safety topics stay general: why stored fluid energy must be controlled. Mechanical Comprehension questions use simple ideal models, not detailed repair procedures.

Hydraulic versus pneumatic power

Both hydraulic and pneumatic systems move energy through a fluid in pipes or hoses to push pistons or turn motors. Hydraulics uses a liquid, usually oil, which barely compresses, so it gives firm, precise motion and very high forces, as in excavators and car lifts. Pneumatics uses compressed air, which squeezes easily, so it is springier and works at lower force but is fast, clean and cheap, as in shop air tools and packaging machines.

Pressure is force divided by area

Pressure tells you how concentrated a force is over a surface:

With force in newtons and area in square meters, pressure is in pascals (Pa). A 600 N force pressing evenly on 0.020 square meters gives

The same force on a smaller area gives a higher pressure.

Pressure units and conversions

One pascal is one newton per square meter, a small amount, so kilopascals (kPa) are common. Useful links:

Normal air pressure at sea level is about 101 kPa, or about 14.7 psi, and 1 psi is roughly 6.9 kPa. So 250 kPa equals 2.5 bar.

Gauge versus absolute pressure

Most pressure gauges read zero when open to the air, so they show gauge pressure: how far above atmospheric the fluid is. Absolute pressure counts from a perfect vacuum:

Taking the atmosphere as about 100 kPa, a tire gauge reading 250 kPa means about 350 kPa absolute. Gas-law calculations must use absolute pressure.

Pressure scale from vacuum at 0 to 350 kPa: atmosphere is about 100 kPa, so a gauge reading of 250 kPa is 350 kPa absolute.

Pascal principle: transmitted pressure change

Pascal's principle says that a change in pressure applied to a confined fluid at rest is passed on undiminished to every part of the fluid and to the walls of its container. If you push a small piston and raise the pressure by 200 kPa, the pressure everywhere in the connected, sealed fluid rises by 200 kPa, including under a large piston far away.

Hydraulic master and slave pistons

In a hydraulic system, a small input piston (often called the master) pushes fluid to a larger output piston (the slave). Because the pressure is the same on both,

The output force grows by the ratio of the areas. That area ratio is the ideal mechanical advantage of the system.

Small input (master) piston of area A1 pushed down with force F1 and large output (slave) piston of area A2 pushing up with force F2, joined by confined oil at the same pressure everywhere.

Worked force multiplication example

An ideal lift has a 5 square centimeter input piston and a 40 square centimeter output piston. A 60 N push is applied to the input.

The output piston pushes with 480 N.

Hydraulic lift with piston faces drawn to scale (5 : 40): a 5 cm² input piston pushed with 60 N and a 40 cm² output piston pushing up with 480 N; 40 ÷ 5 = 8.

Diameter is not piston area

Pistons are circles, and area grows with the square of the diameter:

Double the diameter and the area becomes four times as large. A 4 cm piston compared with a 2 cm piston has an area ratio of

not 2. Square the diameter ratio before using it.

Circles drawn to scale with diameters 2 cm and 4 cm: doubling the diameter gives (4 ÷ 2)² = 4 times the area.

Volume conservation in an ideal lift

A liquid does not compress, so the volume pushed out of the small cylinder equals the volume that enters the large one:

A 4 square centimeter piston moving 30 cm displaces 120 cubic centimeters. Spread under a 20 square centimeter piston, that volume lifts it

A 4 cm² piston moves down 30 cm and a 20 cm² piston rises 6 cm; the shaded volumes are both 120 cm³.

Work and mechanical advantage

A hydraulic press multiplies force but not work. With an area ratio of 5, a 60 N push through 0.30 m gives

The output pushes 300 N but moves only 0.06 m:

Force went up five times; distance went down five times.

Why real hydraulics are not perfect

Real systems fall short of the ideal. Seals rub against cylinder walls and create friction. Fluid flowing through hoses, fittings and valves loses pressure to internal friction. Small leaks let some fluid bypass a piston. Oil compresses very slightly and hoses swell under pressure, so some input motion is absorbed. Trapped air makes this worse. As a result, measured output force and travel are a little less than calculated.

Hydraulic reservoir and pump roles

The reservoir, or tank, stores the oil the system needs, lets heat escape and gives trapped air and dirt time to separate out. The pump draws oil from the reservoir and pushes it into the system. A key idea: a pump creates flow, not pressure. Pressure builds only when that flow meets resistance, such as a load on a cylinder. With nothing resisting, the oil simply circulates at low pressure.

Positive-displacement pump concept

Most hydraulic pumps are positive-displacement types, such as gear, vane or piston pumps. Each turn of the shaft traps a fixed amount of oil and forces it out the outlet, so output flow depends mainly on shaft speed, not on the load. Because the pump keeps forcing oil whether or not it has somewhere to go, a blocked outlet can drive pressure extremely high. That is why these systems need a relief valve.

External gear pump: two meshing gears turn in opposite directions in a housing; oil from the inlet is carried around the outside of each gear in the tooth pockets to the outlet, a fixed amount per turn, and a blocked outlet makes pressure soar, so a relief valve is needed.

Hydraulic pressure relief valves

A pressure relief valve sets the maximum pressure a hydraulic circuit can reach. A spring holds the valve closed. When pressure pushes hard enough to overcome the spring, the valve opens and sends oil back to the tank, so pressure stops rising. This protects the pump, hoses and cylinders from bursting when a cylinder hits the end of its stroke or the load jams.

Spring-loaded relief valve in two panels: closed, the spring holds the poppet on its seat against pressure from the pump; open, the pressure overcomes the spring, the poppet lifts and oil goes to tank.

Check valve versus directional valve

A check valve lets fluid flow in one direction only; reverse flow pushes it shut. It is used to hold a load in place or keep oil from draining back. A directional control valve chooses where flow goes, for example sending oil to one end of a cylinder to extend it or to the other end to retract it, often controlled by a lever, a solenoid or an air signal.

Ball check valve: forward flow pushes the ball off its seat against a light spring and oil passes; reverse flow presses the ball onto the seat and flow is blocked.

Flow controls change speed

A flow control valve uses an adjustable restriction to limit how much oil reaches an actuator each second. Since a cylinder's speed is

where Q is flow rate and A is piston area, cutting the flow slows the piston. It does not change the area, and in an ideal model it does not change the force available at full pressure.

Flow rate is volume per time

Flow rate measures how much fluid passes a point each second or minute:

If 12 L of oil passes in 30 s, then

which is 24 L per minute. Watch the time units.

Continuity through a narrowing line

For a steady flow of liquid, the same volume per second must pass every section of a pipe:

If oil moves at 2 m/s in a 10 square centimeter line that narrows to 5 square centimeters, then

Smaller area means faster flow.

Oil line narrowing from 10 cm² to 5 cm²: speed rises from 2 m/s to 4 m/s, shown by an arrow twice as long.

Hydraulic cylinder extension rate

A cylinder extends as fast as oil fills it. Divide the flow rate by the piston area. With 200 cubic centimeters per second flowing into a cylinder whose piston area is 40 square centimeters,

Cylinder with 200 cm³/s flowing into the cap end and a 40 cm² piston: in one second the added 200 cm³ is a 5 cm slice, so the rod moves at 5 cm/s.

A bigger piston at the same flow moves more slowly.

Hydrostatic pressure with depth

Pressure in a still liquid increases with depth because of the weight of liquid above:

Here is density in kg per cubic meter, g is about 9.8 m/s squared and h is depth in meters. In water 3.0 m deep,

About 29 kPa above surface pressure.

Water tank 3.0 m deep with a depth scale from 0 to 3 m; pressure arrows on the wall grow with depth, and at the bottom 1000 × 9.8 × 3.0 = 29,400 Pa above surface pressure.

Open and closed hydraulic circuits

In an open circuit, oil returns from the actuators to a reservoir at about atmospheric pressure, and the pump draws fresh oil from that tank. Most machinery uses this simple layout. In a closed circuit, oil returning from a hydraulic motor goes straight back to the pump inlet without passing through the tank, which suits some vehicle drives. Either way, the oil itself is reused, not used up.

Open circuit: pump to valve to actuator to tank and back to the pump; closed circuit: pump to hydraulic motor and straight back to the pump with no tank in the loop.

Single-acting cylinders

A single-acting cylinder has fluid power on one side of the piston only. Pressurized fluid extends the rod; a spring, the weight of the load or another outside force returns it when the fluid is allowed to drain. A simple bottle jack is an example: pumping lifts the ram, and opening the release valve lets the weight push the oil back to the reservoir.

Double-acting cylinders

A double-acting cylinder has ports at both ends, so fluid can push the piston both ways. On the rod side, the rod takes up part of the piston face:

With a 50 square centimeter bore and a 10 square centimeter rod, the rod side has 40 square centimeters. At equal pressure, retracting gives less force, and at equal flow it moves faster than extending.

Double-acting cylinder with ports at both ends: the cap-side piston face is the 50 cm² bore, and the rod side is 50 − 10 = 40 cm² because the 10 cm² rod covers part of it.

Hydraulic motor versus cylinder

A hydraulic cylinder produces straight-line motion: its rod pushes or pulls through a fixed stroke. A hydraulic motor produces continuous rotation: pressurized oil flowing through it turns a shaft, much like a pump run in reverse. Pressure sets the torque the motor can deliver, and flow rate sets how fast it spins. Motors drive tracks, winches and conveyors; cylinders lift, press and clamp.

Hydraulic brakes as an application

Vehicle brakes use hydraulics. Pressing the pedal pushes a piston in the master cylinder, raising pressure in the brake fluid. That pressure travels through lines to larger pistons at each wheel, which press the pads or shoes against rotors or drums with a much larger force. Because brake fluid barely compresses, the pedal feels firm. Air in the lines makes it feel spongy and reduces braking.

Hydraulic brake: the pedal pushes a small master-cylinder piston, pressure travels through the brake line to a larger wheel-cylinder piston that presses the pad on the rotor; same pressure, larger area, larger force (not to scale).

Hydraulic lifts and jacks

A hydraulic jack has a small pump piston worked by a handle and a large lifting ram. Each stroke forces a small amount of oil past a check valve into the ram cylinder, raising the ram a little, and the check valve keeps the oil from flowing back. Many short strokes add up to lift a car. A release valve lets the oil return to the reservoir to lower the load slowly.

Hydraulic jack cutaway on a pump stroke: the handle pushes the small pump piston down, the inlet check valve from the reservoir is closed, oil flows through the open outlet check valve into the ram cylinder so the large ram lifts the load; the release valve to the reservoir is closed.

Fluid viscosity and temperature

Viscosity is a fluid's resistance to flowing, its thickness. Hydraulic oil gets thicker when cold and thinner when hot. Cold, thick oil makes pumps work harder and actuators move sluggishly. Hot, thin oil leaks more easily past seals and gives less protective film between moving parts. That is why manufacturers specify an oil grade and an operating temperature range, and why some systems use coolers or heaters.

Filters and contamination

Dirt, metal particles and water are leading causes of hydraulic failures. Tiny particles wear pumps and valves, and clog small passages. Filters in the suction, pressure or return lines trap contaminants. As a filter fills with dirt, it restricts flow more, raising the pressure drop across it. Many filters have an indicator or bypass. Clean oil, sealed reservoirs and regular filter changes keep a system reliable.

Leak versus trapped air symptoms

Different faults show different signs. An external leak shows up as oil on the machine or floor and a falling reservoir level. An internal leak, such as past a worn piston seal, may let a cylinder slowly drift under load with no visible oil. Trapped air tends to cause spongy, jerky motion, foamy oil and noisy pumps. Neither cause should be assumed from a single symptom.

What pneumatics uses

Pneumatic systems use compressed air, or sometimes another gas such as nitrogen, as the working fluid. Air is free, does not need a return line because it vents to the atmosphere after use, and a small leak does not create an oily mess. Because air compresses, pneumatic actuators are quick but less precise in position under changing loads. Typical uses include impact wrenches, nail guns, paint sprayers, door openers on buses and pick-and-place machines on assembly lines.

Air compressors and stored energy

A compressor draws in outside air and squeezes it into a smaller volume, raising its pressure. The compressed air is stored in a tank called a receiver, which smooths demand and lets the compressor rest between cycles. That stored air holds a lot of energy. Even with the compressor turned off, a full receiver can drive tools or burst a hose.

Air preparation components

Air from a compressor carries moisture, dirt and sometimes oil. Before it reaches tools and valves, it usually passes through an air preparation unit. A filter removes particles and liquid water. A regulator sets a steady working pressure. In some systems, a lubricator adds a fine oil mist for tools that need it. This trio is often abbreviated FRL, for filter, regulator, lubricator.

Pressure regulator purpose

A pressure regulator keeps the downstream pressure at a chosen setting even when the supply pressure from the receiver rises and falls. Lowering the setting reduces actuator force and saves air; raising it, within ratings, gives more force. A regulator cannot make pressure higher than its supply.

Directional air valves

Directional valves route compressed air to one side of a cylinder and open the other side to exhaust. They are described by ports and positions, such as a 5/2 valve with five ports and two positions. They may be shifted by hand, by a solenoid or by an air signal, and springs often return them.

Pneumatic cylinders and return springs

A single-acting air cylinder often uses an internal spring to retract. When air enters, it must overcome that spring as well as the load, so the useful output is

At 500 kPa on 0.0020 square meters, air gives 1000 N; with a 150 N spring, about 850 N remains.

Single-acting air cylinder with a return spring on the rod side: air at 500 kPa on a 0.0020 m² piston gives 1000 N, the spring pushes back 150 N, and the rod delivers a net 850 N.

Air pressure and an ideal force

The force a pneumatic cylinder can push equals gauge pressure times piston area. With 600 kPa gauge on a 0.0025 square meter piston,

Convert kPa to Pa before multiplying.

Boyle law at constant temperature

For a fixed amount of gas held at constant temperature, pressure and volume are inversely related:

Halve the volume and the pressure doubles. Both pressures must be absolute, not gauge. Any volume unit works as long as both match.

Same gas sample squeezed at constant temperature from volume V at pressure P to volume V/2 at pressure 2P, with pressures absolute.

Boyle-law worked example

Air at 100 kPa absolute fills 12 L and is squeezed slowly to 3 L.

That is absolute pressure. With an atmosphere of about 100 kPa, a gauge would read about 300 kPa.

Temperature affects compressed gas

In a sealed, rigid tank, warming the gas raises its pressure:

Temperatures must be in kelvin and pressures absolute. A tank at 400 kPa absolute and 280 K, warmed to 308 K, reaches

Compressed air is not an ideal liquid

Hydraulic formulas assume an incompressible fluid. Air is not. When a pneumatic cylinder meets a load, the air inside compresses a little before the piston moves, and if the load changes, the piston position shifts. That springiness cushions shocks but makes holding a precise position hard. Air also heats when squeezed and cools when it expands, so simple Boyle-law answers are estimates.

Air flow and actuator speed

How quickly a pneumatic cylinder moves depends mainly on how fast air can flow in and out. Narrow hoses, small valves and restricted exhausts slow it down. Flow control valves on the exhaust side are a common way to set speed smoothly. Raising pressure helps somewhat, but the springy air makes speed less predictable than in hydraulics.

Energy tradeoffs in pneumatics

Compressed air is convenient but expensive to make. Compressing air heats it, and most of that heat is lost as the air cools in the receiver and lines. Leaks waste energy continuously, even when no tools run. Overall, only a small fraction of the electricity driving a compressor ends up as useful work at the tool. Fixing leaks and lowering pressure to what the job needs save energy.

Pressure times area applies to both media

The force rule is the same for oil and air:

A hydraulic cylinder at 10 MPa and an air cylinder at 0.6 MPa use the same formula. Hydraulics usually wins on force because it runs at much higher pressure, not because the physics differs. Use consistent units: Pa with square meters gives newtons.

Pressure and flow solve different problems

Pressure and flow answer different questions. Pressure, times area, decides how much force an actuator can push with. Flow rate, divided by area, decides how fast it moves. A cylinder that is strong enough but slow needs more flow, not necessarily more pressure. A cylinder that moves quickly but stalls under load needs more pressure or a larger piston.

Why equal piston pressure is not equal force

Two pistons on the same fluid see the same pressure, but larger area means larger force. At 300 kPa,

Four times the area gives four times the force.

Equivalent area units

Area units convert by the square of the length factor. Since 1 m equals 100 cm,

So 35 square centimeters equals 0.0035 square meters. Dividing by 100 instead of 10,000 is a common error.

The cylinder displacement calculation

The volume of fluid a cylinder takes in during a stroke is

where A is piston area and s is stroke length. A 20 square centimeter piston moving 15 cm needs

That is 0.30 L.

Pressure drop through restrictions

When fluid flows through a narrow spot, such as a partly closed valve, a clogged filter, a kinked hose or a small fitting, it loses pressure across that restriction. The more restrictive the passage or the higher the flow, the bigger the pressure drop. That lost pressure turns into heat. With no flow, the pressure on both sides of a restriction evens out.

Hydraulic accumulators

An accumulator stores hydraulic energy by pushing oil against a compressed gas charge, usually nitrogen, or a spring. It can supply bursts of flow, smooth pressure pulses and provide emergency power. Because it holds pressure even when the pump is off, an accumulator must be safely discharged before work on the system.

Piston accumulator in two panels: oil coming in pushes the piston up and squeezes the nitrogen gas; then the gas pushes the oil back out to the system line; it holds pressure with the pump off, so discharge it first.

Pneumatic exhaust and mufflers

After air has pushed a piston, the directional valve releases it to the atmosphere through an exhaust port. That rapid release is loud. Mufflers, also called silencers, are fitted to exhaust ports to reduce noise, and some include restrictors to adjust speed.

Hydraulic return and tank line

After oil has done its work in an actuator, it must go back to the reservoir through the return, or tank, line. This line runs at low pressure. A blocked return line can stop an actuator or raise pressure where it is not expected.

Pressure gauge placement

A pressure gauge reports the pressure only where it is connected. A gauge at the pump outlet can read normal while a clogged filter or valve downstream starves the cylinder. Technicians often compare readings at several points to locate a restriction. A gauge measures pressure, not flow or speed.

Pump line through a clogged filter to a starved cylinder: a gauge before the filter reads normal and a gauge after it reads low, because each gauge reads only the pressure where it is connected.

Symptoms require several hypotheses

A single symptom can come from several causes. A slow cylinder might mean low pump flow, a partly closed flow control, an internal leak past a seal, thick cold oil or a clogged filter. Weak force might come from low pressure, a misadjusted relief valve or a leak. Good troubleshooting lists possible causes, then checks them with measurements.

Never use skin to seek leaks

Never run your hand along a hose to find a leak. A pinhole jet of hydraulic oil can pierce skin and inject fluid under it. The wound may look small but can cause severe tissue damage and needs emergency medical care. Compressed air jets can also break skin. Use cardboard or another tool to locate leaks with the system safely depressurized when possible.

Hazardous energy isolation

Fluid power systems can move unexpectedly even when the motor is off. Accumulators, raised loads, compressed air in receivers and trapped pressure in lines all store energy. Before maintenance, authorized workers follow lockout and tagout procedures: shut down, isolate energy sources, release or block stored pressure, support raised loads, and verify that nothing can move before work begins.

Compressed air cleaning restrictions

Compressed air can blow dust and chips off parts, but it is not a toy. Workplace rules limit the pressure of air used for cleaning and require guarding and eye protection. Never point an air nozzle at yourself or anyone else, or use it to dust off clothing or skin. Air forced into the body can cause serious injury.

Eye and hose hazards

Air or oil jets can throw chips and dust into eyes, so safety glasses are standard. A hose that comes loose under pressure can whip violently and strike people. Use rated fittings and restraints, depressurize before disconnecting, and inspect hoses for cracks, bulges or wear.

Pressure rating is a hard limit

Every hose, fitting, cylinder and tank has a maximum working pressure set by its manufacturer. Exceeding it can cause a sudden burst, flying parts or a high-pressure jet. Do not substitute lower-rated parts or raise relief valve settings to get more force. If more force is needed, the correct fix is a larger piston or a system designed for higher pressure, not overloading existing parts.

Reading a basic hydraulic diagram

Hydraulic circuits are drawn with standard symbols. A circle with a filled triangle shows a pump; an open-topped box near the bottom is the reservoir. Rectangles divided into squares are directional valves, with arrows showing flow paths. A long rectangle with a piston line is a cylinder. Trace flow from pump through valves to the cylinder and back to tank.

Basic hydraulic schematic: pump (circle with filled triangle) draws from an open-topped reservoir; a normally closed relief valve with a spring and a dashed pilot line returns oil from the pressure line down to the tank; a two-square directional valve sends oil to a cylinder with a piston line and rod, with the return line to the tank.

Reading a basic pneumatic diagram

Pneumatic symbols look much like hydraulic ones, but the triangles in pumps, compressors and motors are drawn hollow to show air instead of filled for liquid. A compressor feeds a receiver, then a filter, regulator and lubricator. A directional valve sends air to a cylinder. Exhaust ports point to atmosphere, often marked with a small triangle or a muffler symbol.

Pneumatic schematic with symbols: compressor (circle with hollow triangle) to receiver, then filter, regulator and lubricator, then a two-position directional valve that sends air to a cylinder; its exhaust ports are hollow triangles to atmosphere.

Worked comparison: force versus travel

An ideal press has a 3 square centimeter input piston and an 18 square centimeter output piston. A 40 N input force gives

If the input moves 24 cm, the output moves

Six times the force, one sixth the travel.

Ideal press: a 3 cm² input piston pushed with 40 N moves down 24 cm, and the 18 cm² output piston pushes up 240 N and rises 4 cm; six times the force, one sixth the travel.

Worked comparison: pipe velocity

A pump delivers 0.60 L/s, which is 600 cubic centimeters per second, through a line of 3.0 square centimeters. The fluid speed is

That is 2.0 m/s. In a 6.0 square centimeter line the same flow would move at 1.0 m/s.

Worked comparison: air spring

A sealed air spring holds 6.0 L at 200 kPa absolute. A load squeezes it slowly to 4.0 L. By Boyle's law,

Squeezing further keeps raising the pressure, so the spring stiffens.

Common ASVAB traps

Watch for these traps. Pressure is the same throughout a connected fluid, but force is not; bigger pistons push harder. Bigger pistons also move less and more slowly. Using diameters as areas understates the ratio; square them. Gas laws need absolute pressure and kelvin temperatures. Mismatched area units cause factor-of-10,000 errors. No hydraulic system creates energy; force gain always costs travel.

Final recap and independent practice

Pressure is force per area. Pascal's principle spreads a pressure change through a confined fluid, so output force grows with the area ratio while travel shrinks by the same ratio. Speed equals flow divided by area. Air obeys Boyle's law, and its pressure rises when it is heated in a sealed tank. Pumps create flow; relief valves cap pressure; check valves allow one-way flow; regulators set air pressure. Practice: a 2 square centimeter piston pushed with 30 N drives a 10 square centimeter piston. Output force? Answer: 150 N. If the small piston moves 15 cm, the large one moves 3 cm.

Quick review

Pressure: definition and SI unit
: force (N) divided by area (m²) gives pascals; 1 bar = 100 kPa, sea-level air is about 101 kPa (14.7 psi). Note .
Hydraulic force multiplication (Pascal's principle)
Pressure is equal on both pistons, so and . A 60 N push on 5 cm² drives a 40 cm² piston with 480 N.
Trap: piston diameters given instead of areas
Area grows with diameter squared: . A 4 cm piston has 4 times the area of a 2 cm piston, not 2 times, so square the diameter ratio.
Hydraulic press: what is the trade-off for more force?
Volume is conserved, , so the large piston moves less. Six times the force means one sixth the travel; work in equals work out ideally.
Cylinder speed from flow rate
: flow rate (volume per time) divided by piston area. 200 cm³/s into a 40 cm² piston gives 5 cm/s. Pressure sets force; flow sets speed.
Boyle's law for compressed air
at constant temperature, using absolute pressures. Air at 100 kPa abs in 12 L squeezed to 3 L reaches 400 kPa abs (about 300 kPa gauge).
Gauge vs absolute pressure
, with the atmosphere about 100 kPa. A tire gauge reading 250 kPa means about 350 kPa absolute. Gas-law problems require absolute pressure.
Hydraulic valves: relief, check and directional
Relief valve: opens to tank to cap maximum pressure. Check valve: allows flow one way only, holding loads. Directional valve: routes flow to extend or retract a cylinder. A pump makes flow, not pressure.

What next?

← Previous: Inclined Planes, Wedges and Screws

About this lesson

The middle sections cover pumps, relief and check valves, flow rate, continuity through a narrowing line, and single-acting versus double-acting cylinders. The pneumatic half explains compressors, regulators, return springs and Boyle's law at constant temperature, followed by safety topics such as hazardous energy isolation and never using skin to find leaks.

Mechanical Comprehension questions on fluids usually test one relationship at a time: pressure times area, area ratios, or the force-versus-travel tradeoff. A Common ASVAB traps section targets those. Budget about 110 minutes, then take the 40-question lesson test for this topic.

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