Lesson Goal
In this lesson you will solve motion problems with one vehicle and with two. You will use distance equals rate times time, keep units consistent, combine speeds for objects moving apart, toward each other or in a chase, account for head starts, and compute true average speed for round trips and trips that include stops.
The Motion Relationship
Every motion problem uses the same link between distance, rate and time.
If you know any two of the three, you can find the third: divide distance by time for rate, or divide distance by rate for time. The formula assumes a steady speed, or an average speed over the trip.
Unit Consistency
The units of rate decide the units of time and distance. A speed in kilometers per hour needs time in hours. If a train runs at 72 km/h for 25 minutes, convert first:
Multiplying 72 by 25 directly would give 1,800, an impossible answer.
One-Vehicle Distance Problems
To find distance, multiply speed by time. A pickup driving 46 mph for 4.5 hours travels
Write the time as a decimal number of hours before multiplying.
One-Vehicle Time Problems
To find time, divide distance by speed. A 275-mile drive at 50 mph takes
Convert the decimal part to minutes by multiplying by 60: 0.5 hour is 30 minutes, so the trip lasts 5 hours 30 minutes.
One-Vehicle Rate Problems
To find speed, divide distance by time. A courier covers 228 miles in 4 hours 45 minutes. Write the time as 4.75 hours, then divide:
Opposite-Direction Motion
When two objects leave the same point in opposite directions, the distance between them grows by the sum of their speeds. Two hikers walking away from a trailhead at 3 mph and 4 mph separate at 7 mph. After 2.5 hours they are
apart.
Moving Toward Each Other
When two objects approach each other, the gap closes at the sum of their speeds. Two buses 380 km apart drive toward each other at 90 km/h and 100 km/h. The gap shrinks by 190 km each hour, so they meet after
Same-Direction Catch-Up
When a faster object chases a slower one on the same route, the gap shrinks by the difference of their speeds. A bus is 18 miles ahead at 48 mph, and a car follows at 57 mph. The car gains 9 miles each hour, so it catches the bus in
Head Starts in Time
Sometimes the lead is given as time rather than distance. Turn it into distance first. A boat leaves at 16 mph; a second boat follows 1 hour 15 minutes later at 24 mph. The lead is
Closing at 8 mph, the second boat catches up 2.5 hours after it leaves.
Meeting Problems With Unequal Start Times
Two towns are 260 miles apart. Car A leaves one town at 40 mph; one hour later Car B leaves the other at 70 mph. In that first hour A covers 40 miles, leaving a 220-mile gap. Together they close 110 miles per hour, so they meet 2 hours after B starts, 3 hours after A starts.
Round Trips
A round trip covers the same distance twice, often at different speeds. Treat each leg separately. A technician drives 84 miles to a site at 42 mph, taking 2 hours, and returns at 56 mph, taking 1.5 hours. The whole trip is 168 miles in 3.5 hours. Add distances and times before finding any average.
Average Speed
Average speed is total distance divided by total time, not the average of the speeds. For the technician's round trip,
Averaging 42 and 56 would give 49 mph, which is wrong because more time was spent at the slower speed.
Equal-Distance Average-Speed Trap
When two legs have equal distance, the average speed is pulled toward the slower speed. Going 30 mph one way and 60 mph back gives
not 45. The slow leg lasts longer, so it counts more.
Rest Stops and Total Trip Time
If a question asks for overall average speed including a stop, add the stop to total time, but add no distance for it. A driver goes 104 miles at 52 mph (2 hours), rests 30 minutes, then goes 90 miles at 60 mph (1.5 hours). Total: 194 miles in 4 hours, or 48.5 mph overall.
Build a Motion Table
For two-object problems, set up a small table with one row per traveler and columns for rate, time and distance. Fill in what is given, use a variable for the unknown, and write how the rows relate: equal distances for a catch-up, distances that add to the gap for a meeting. Then form one equation and solve.
Relative-Speed Shortcut
Instead of tracking two travelers, treat the gap as one object. Its speed is the sum of the two speeds if they move toward or away from each other, and the difference if one chases the other. Then time equals the gap divided by that relative speed. This turns most two-vehicle questions into a single division.
Worked Example 1 — Meeting Time
Problem: Two trains 420 km apart run toward each other at 110 km/h and 100 km/h. When do they meet?
Step 1: The trains move toward each other, so the gap closes at the sum of their speeds (the relative speed).
Step 2: Divide the distance by the relative speed.
Answer: The trains meet after 2 hours.
Check: In 2 hours, one train goes
and the other goes
the full gap.
Worked Example 2 — Catch-Up
Problem: A jogger running 6 mph is 0.6 mile ahead of a friend running 8 mph. How long until the friend catches up?
Step 1: Both move the same direction, so the gap shrinks by the difference in speeds.
Step 2: Divide the head start by the gain per hour.
Step 3: Change hours to minutes by multiplying by 60.
Answer: The friend catches up in 18 minutes (0.3 hour).
Check: In 0.3 hour the friend runs
and the jogger runs
mile, exactly the head start.
Worked Example 3 — Time-Based Head Start
Problem: A truck leaves a depot at 45 mph. Forty minutes later a car leaves the same depot on the same road at 60 mph. When does the car catch the truck?
Step 1: Find the truck's head start. Change 40 minutes to hours:
(
)
Step 2: Find how fast the car gains on the truck.
Step 3: Divide the head start by the gain per hour.
Answer: The car catches the truck 2 hours after the car leaves.
Check: In 2 hours the car goes
The truck has driven 2 hours 40 minutes, which is
plus 30 miles, also 120 miles. They are at the same spot.
Worked Example 4 — Round-Trip Average Speed
Problem: A pilot flies 150 miles out at 50 mph and back at 75 mph. What is the average speed for the round trip?
Step 1: Average speed = total distance ÷ total time. Find the time out.
Step 2: Find the time back.
Step 3: Total distance and total time.
Step 4: Divide.
Answer: The average speed is 60 mph, not the 62.5 mph you get by averaging the two speeds. The pilot spends more time at the slower speed, so the average is pulled toward 50.
Check: 60 mph × 5 hours = 300 miles, the full round trip.
Worked Example 5 — Stop Included
Problem: A driver goes 63 mph for 2 hours, stops 30 minutes, then goes 56 mph for 1.5 hours. Find the overall average speed.
Step 1: Find the distance of each driving part. First part:
Step 2: Second part (
plus half of 56 = 28):
Step 3: Add the distances.
Step 4: Add all the time, including the 30-minute stop (0.5 hour), because the clock keeps running.
Step 5: Divide total distance by total time.
Answer: The overall average speed is 52.5 mph.
Check:
The answer is below both driving speeds, which makes sense because the stop adds time with no distance.
Common Motion Traps
Averaging the speeds: for a round trip at two speeds, the simple mean is too high because more time is spent at the slower speed. Divide total distance by total time.
Forgetting the stop: if the question says "including the stop," the break adds time but no distance.
Wrong relative speed: add speeds for approaching or separating objects, subtract for a chase.
Ignoring a time head start: convert the early start into a lead distance before dividing.
Mixed units: change minutes to hours before using a speed in miles per hour.
Quick Review
Use
and its rearrangements, with time in the same unit as the speed. For two travelers, find the relative speed: the sum when they approach or separate, the difference in a chase. Turn a time head start into a distance lead, then divide the gap by the relative speed. For unequal start times, subtract the early traveler's distance from the gap first. Average speed is total distance over total time; for equal legs it falls closer to the slower speed. Include rest stops in total time when the question asks for the overall average.
